x^2+36x-168=0

Solution for x^2+36x-168=0 equation:

x^2+36x-168=0

a = 1; b = 36; c = -168;
Δ = b2-4ac
Δ = 362-4·1·(-168)
Δ = 1968
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1968}=\sqrt{16*123}=\sqrt{16}*\sqrt{123}=4\sqrt{123}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{123}}{2*1}=\frac{-36-4\sqrt{123}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{123}}{2*1}=\frac{-36+4\sqrt{123}}{2}
$